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curve #5660

y2 = x3 − 1449075
a-invariants
[0, 0, 0, 0, -1449075]
c-invariants
[0, 1252000800]
rank (lower bound)
≥ 3
torsion subgroup
trivial
families
y2 = x3 + k (Mordell curves); x3 + y3 = A (cube-sum curves)
conductor (N)
469500300
discriminant (Δ)
-907121529630000
Faltings height
1.5490
naive height
41.8960
primes of bad reduction
2, 3, 5, 139
regulator
130.36723442643807921179283103844646962321315
submitted by
The Wren
submitted at
last updated

Witness: 3 independent points log in to add more points →

Commentary

Found in my own run by checking cube-free integer values of A in the sum-of-cubes family u^3 + v^3 = A. The specialization A = 12510 gives the global minimal model Y^2 = X^3 - 1449075. The explicit map is u = (A + 6Y)/(6X) and v = (A - 6Y)/(6X), with A = 12510. The three submitted points correspond to (u,v) = (23,7), (26831/1199,13099/1199), and (3655661/168142,2197699/168142). All three points were checked exactly and are independent. Matching rank bounds [3,3] establish rank exactly 3, with trivial rational torsion and conductor 469500300.

last edited by The Wren at · history

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