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curve #5569

y2 + y = x3 + 6821149356910058524404436623298402
a-invariants
[0, 0, 1, 0, 6821149356910058524404436623298402]
c-invariants
[0, -5893473044370290565085433242529819544]
rank (lower bound)
≥ 17
torsion subgroup
trivial
family
y2 = x3 + k (Mordell curves)
conductor (N)
809086259038223489432482561001918463920931331342328985448022657409 ☆ record for Mordell curves, rank ≥ 17
discriminant (Δ)
-20100129933286586147971164262970660399187697064537478985485226878011787
Faltings height
12.1688
naive height
169.3338
primes of bad reduction
3, 7, 13, 71, 1129, 41103847444286828222618671
regulator
5131924913845676431.26367610294808853810054460689456388229794496493466343
submitted by
wgxli
submitted at
last updated

Witness: 17 independent points log in to add more points →

Commentary

Specialization of a Mordell curve over Q(T) with generic rank 4. The curve is a member of a universal parameterized rank-4 family that includes every rank >= 4 Mordell curve over Q at least once up to isogeny. Moreover, this family achieves the minimum conductor degree of 12 for a non-constant Mordell Q(T) curve of generic rank 4, and accounts for all such degree-12 curves up to Q(T)-isogeny. The construction is as follows. Choose a rational point (a, b, c, d) on the Burkhardt quartic 1 + a^3 + b^3 + c^3 + d^3 + 3abcd = 0 subject to appropriate non-singularity conditions. Let A := a^3 + 1, R := a^2 d^2 - bc, H(T) := bT^2 - cT - ad, G(T) := (b^3 - d^3)T^3 + 3bRT^2 - 3cRT - (2a^3 d^3 + c^3 + d^3). Define the polynomial Phi_{a,b,c,d}(T) := A^2/4 (G(T)^2 + 4Ad^3 H(T)^3). Then the curve Y^2 = X^3 + Phi_{a,b,c,d}(T) has generic rank 4 over Q(T), and moreover every rank >= 4 Mordell curve over Q arises as some specialization. This particular curve arises as (a, b, c, d, T) = (-43/36, -5/12, 1/4, 7/9, 4209911/23085591).

last edited by wgxli at · history

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